1. The problem statement, all variables and given/known data The 10kg block has an initial velocity of 2m/s at the bottom of the ramp and slides up the ramp with a constant applied horizontal force F=75N as shown. Find the maximum height h that the block can reach on the ramp. We're using cos(theta/%)=.8 & sin(theta/%)=.6 m=10kg | V1=2m/s | F=75N | Y2=? | Y1=0 | coefficient of friction(#)= .4 2. Relevant equations K1 + Ug1+ Ue1+ W'1-2= K2 + Ug2 + Ue2 3. The attempt at a solution K1= .5m(V1)2 V1=2 ==20 K2= .5m(V2)2 V2=0 ==0 Ug1= mgY1 Y1=0 ==0 Ug2= mgY2 = 98Y2 (elastics are 0) W'1-2 = WF+Wf = [-#*mgcos(%)*(y2/sin(%))] + [Fcos(%)*(Y2/sin(%))] =[(-.4)(10)(9.8)(.8)*(Y2/.6)] + [(75)(.8)*(Y2/.6)] =47.733Y2 Energy Equation: 20+0+0+47.733Y2 = 0 + 98Y2 + 0 Y2=.398 BUT the answer is .249m. If you could review my work, and help me find out where I went wrong, it would be greatly appreciated.