Hello, I need soe help please, i cant seem to get this one. 1. The problem statement, all variables and given/known data A 0.20-kg mass is hung from a vertical spring of force constant 55 n/m. When the spring is released from its unstretched equilibrum position, the mass is allowed to fall. Use the law of conservation of energy to determine: a) the speed of the mass after it falls 1.5cm b) the distance the mass will fall before reversing direction Books answers: a) 0.48 m/s b) 0.071m 2. Relevant equations Eg = mgh Ee =0.5 k x^2 Ek= 0.5 m v^2 3. The attempt at a solution I have tried several things, but have erased them. I came up with 0.24 m/s for a) several times.