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Energy in Thermal Processes

  1. Jan 14, 2013 #1
    A 97.6-g lead ball with an initial temperature of 20°C, is dropped from rest from a height of 4.57 m. The collision between the ball and ground is totally inelastic. Assuming all the ball's kinetic energy goes into heating the ball, find its final temperature.

    PLEASE HELP ME UNDERSTAND THIS PROBLEM STEP-BY-STEP
     
  2. jcsd
  3. Jan 14, 2013 #2

    gneill

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    Staff: Mentor

    You'll have to re-read the forum rules. You need to follow the posting template and provide an attempt so that we can know how to help you; we cannot provide answers or do your homework for you.
     
  4. Jan 14, 2013 #3
    This is what I think I would do:
    So I would us the potential energy equation: P.E.=mgh
    so --> P.E.= (.0976 kg)(9.8m/s^2)( 4.57m)
    P.E. = 4.371J

    With this I'll use the equation: Q=mcT

    4.371J =(.0976kg)(128 J/Kg(°C) )( Tf-20°C)

    Ans so I'll solve for Tf


    SO IS THIS RIGHT?? PLEASE HELP
     
  5. Jan 14, 2013 #4

    gneill

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    Staff: Mentor

    That should work.
     
  6. Jan 14, 2013 #5
    Thanx!
     
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