# Energy in Thermal Processes

A 97.6-g lead ball with an initial temperature of 20°C, is dropped from rest from a height of 4.57 m. The collision between the ball and ground is totally inelastic. Assuming all the ball's kinetic energy goes into heating the ball, find its final temperature.

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gneill
Mentor
A 97.6-g lead ball with an initial temperature of 20°C, is dropped from rest from a height of 4.57 m. The collision between the ball and ground is totally inelastic. Assuming all the ball's kinetic energy goes into heating the ball, find its final temperature.

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This is what I think I would do:
So I would us the potential energy equation: P.E.=mgh
so --> P.E.= (.0976 kg)(9.8m/s^2)( 4.57m)
P.E. = 4.371J

With this I'll use the equation: Q=mcT

4.371J =(.0976kg)(128 J/Kg(°C) )( Tf-20°C)

Ans so I'll solve for Tf

gneill
Mentor
This is what I think I would do:
So I would us the potential energy equation: P.E.=mgh
so --> P.E.= (.0976 kg)(9.8m/s^2)( 4.57m)
P.E. = 4.371J

With this I'll use the equation: Q=mcT

4.371J =(.0976kg)(128 J/Kg(°C) )( Tf-20°C)

Ans so I'll solve for Tf