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**1. The diagram above shows the lowest four descrete energy levels of an atom. An electron in the**

*n*=4 state makes a transition to the*n*=2 state, emitting a photon of wavelength 121.9 nm(a)Calculate the energy level of the n=4 state.

(b)Calbulate the momentum of the photon.

**The photon is then incident on a silver surface in a photoelectric experiment, and the surface emits an electron with maximum possible kinetic energy. The work function of the silver is 4.7eV**

(c) Calculate the kinetic energy, in eV, of the emitted electron.

**2. E=hf**

E= pc

h=6.63 x 10[tex]^-34[/tex]J.s

h=4.14 x 10[tex]^-15[/tex]eVs

KEmax = hf-work function

work function = hf0

v=fλ

λ=h/p

E= pc

h=6.63 x 10[tex]^-34[/tex]J.s

h=4.14 x 10[tex]^-15[/tex]eVs

KEmax = hf-work function

work function = hf0

v=fλ

λ=h/p

**3. .....might come back with this..**

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