1. The problem statement, all variables and given/known data PART D this is an example from my textbook, i do not understand the result however 2. Relevant equations U = W = Q^2/(2v) = 0.5 CV^2 = 0.5 QV the charge once connected Q1 640 micro F Q2 320 micro F V1=V2 = 80V (equating the charges to total Q0 initially stored in the capacitor) 3. The attempt at a solution part d asks to find the total energy in the system, however in the answers the book found the total energy in the system to be 0.038J ( once both capacitors are connected) however the energy required to charge up the first capacitor is 0.058J - i thought this should be the total energy of the system. this does not make sense, how can there be energy loss, as the formula didn't take account of energy loss. The book found the energy in the system by working out the charge in each capacitor the working out the total energy using equation 2 i just can't see how method took account of energy loss, using formulas to my understanding that did not consider energy loss.