A crate of mass 11.0 kg is pulled up a rough incline with an initial speed of 1.50 m/s. The pulling force is 100 N parallel to the incline, which makes an angle of 16.5° with the horizontal. The coefficient of kinetic friction is 0.400, and the crate is pulled 5.65 m.(adsbygoogle = window.adsbygoogle || []).push({});

(b) How much mechanical energy is lost due to friction?

well, this is what i came up with

to find the energy lost i thought F - f

so to find f = u_kN

N = (mgsin16.5)

f = .400(30.62)

f = 12.25

100 - 12.25 = 87.75 is incorrect

what am i doing wrong?

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# Energy lost due to friction

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