Energy Lost to Heat ~ Spring (Solved) 1. The problem statement, all variables and given/known data --->What is the energy lost to heat?<--- spring mass = 15g = .015kg spring constant = 220 J/m^2 spring is compressed 5cm (.05m) then released to achieve maximum height of 102 cm (1.02 m) 2. Relevant equations U = .5(k)(x)^2 where U is the potential energy of a spring, k is the spring constant, and x the compression length. K=.5(m)(v)^2 where K is kinetic energy, m is a mass, and v is velocity Ug = mgy where Ug is gravitational potential energy, m is a mass, g is gravity, y is height in y direction ME (Mechanical Energy) = Kinetic Energy K + Potential Energy (Ug) 3. The attempt at a solution Ok, I understand that this is a Conservation of Energy question. I don't know how to go about it. I need to find energy lost to heat. U = .5(220J/m^2)(.05m)^2 = 0.275 Joules <--Spring potential energy At it's highest point...Kinetic Energy = 0 and Potential Energy is at its greatest. Ug= mgy = (.015kg)(9.81m/s^2)(1.02m) = .15J _______ This is where I'm lost, would anybody mind pointing me in the correct direction?