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irrrjntlp
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Homework Statement
A roller coaster is lifted up 50m above the ground to the top of the first hill and then glides down around the track at the bottom. If it had a velocity of 3.0 m/s at the top of the lift and loses 10% of its total energy to friction as it glides down, what is the roller coaster's final speed at the bottom. Sorry, I can't remember the mass (in the question, i didn't actually forget it).
Thanks for any help!
Homework Equations
v2^2 = v1^2 + 2g (y1-y2) <- not sure if this is correct..
The Attempt at a Solution
v2^2 = 3^2 + 2(9.8)(50-0)
v2^2 = 9 + 980
v2^2 = 989
V2 = 31.4 m/s
I'm not sure how to apply the friction acting against without a mass...
9.8 - (9.8 x .1)
8.82 <- Maybe use this as acceleration instead..