A H-atom when in its lowest energy state consiste of a proton nucelus of charge +e and an electron of charge -e and mass 9.11e-31. In the Bohr model of the atom, the electron moves around the nucleus in an aprrox. circular orbit of radius .51e-10m. The speed of the electron when in this lowest energy orbit is 2.2e6m/s. Determine the speed that another electron far from the hydrogen atom must have in order to ionize the h-atom during a collision. In the final state, the two electrons and proton are considered at rest and very far from each other. Convert the answer to energy units of electron volts.
The Attempt at a Solution
I set is up as .5mv(i)^2-(kappa)(e^2)/radius=0. I came up with 3.26e6m/s but one, something about this setup is bugging me and two, how do I convert to electron volts?