(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The z component of the magnetic dipole moment due to the spin of an electron about its axis is μ_{z}= +/- eh/4∏m, where h = 6.63 x 10^{-34}J s is Planck's constant. A) If μ_{z}is parallel to a magnetic field of 10 T, how much energy in electron volts must be supplied to reverse its direction so that it is opposite to the field?

B) Find the ratio of this energy to the 13.6 eV needed to remove an electron from a normal hydrogen atom.

2. Relevant equations

μ_{z}= +/- eh/4∏m

(μ) (2B)/h = V

3. The attempt at a solution

First find μ_{z}:

μ_{z}= (+/- 1.60 x 10^{-19}C) (6.63 x 10^{-34}Js/ (4∏) (9.11 x 10^{-31}kg)

μ_{z}= 9.30 x 10^{-24}Am^{2}

Find V:

μ = hV/2 B

V = (μ) (2B)/h = (9.30 x 10^{-24}Am^{2}) (2 * 10 T)/(6.63 x 10^{-34}J s)

V = 2.81 x 10^{6}V

B) (2.81 x 10^{6}V)/(13.6 V) = 2.07 x 10^{5}

Is this correct?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Energy of a magnetic dipole moment

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**