Energy of a Rolling Object

1. Nov 15, 2007

Jtappan

1. The problem statement, all variables and given/known data

A solid sphere of mass 0.599 kg rolls without slipping along a horizontal surface with a translational speed of 5.31 m/s. It comes to an incline that makes an angle of 33° with the horizontal surface. Neglect energy losses due to friction.

(a) What is the total energy of the rolling sphere?
________ J
(b) To what vertical height above the horizontal surface does the sphere rise on the incline?
________ m

2. Relevant equations

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3. The attempt at a solution

What equations would I use for this problem? any other information would be great thanks!

2. Nov 15, 2007

Dick

You can't find ANY equations?

3. Nov 16, 2007

Bill Foster

Kinetic energy is given by $$K=\frac{1}{2}mv^2$$

Rotational energy is given by $$T=\frac{1}{2}I\omega^2$$

The moment of intertia for a solid sphere is given by $$I=\frac{2}{5}mr^2$$

Potential energy is given by $$U=mgh$$

4. Nov 16, 2007

Bill Foster

You will need one more equation to solve this.

$$v=\omega r$$

5. Nov 16, 2007

vasra

Some hints from a fellow learner:

- How do you calculate linear (aka translational) movement energy for a body?
- What is the difference between kinetic and potential energies and how do you calculate them?
- Is energy conserved, if there is no friction or drag (aka energy losses)?