1. The problem statement, all variables and given/known data A solid metal ball of radius 0.500m, and a mass of 1.50 kg, is found to be rolling down a sloped floor whose angle is 30.0° to the horizontal (assume no slipping). The ball has a final angular velocity of 2.00 rad/s. What is the total energy of the ball when it it is 2.00m from the bottom of the slope? (Assume there is no friction) 2. Relevant equations Energy final = 1/2mv^2 + 1/2Iw^2 + mghf v= rw v= .5 (2) = 1m/s I = moment of inertia = 2/5(mr^2) 3. The attempt at a solution Ef= 1/2(1.5kg)(1m/s^2)+ 1/2(2/5(1.5kg(.5m^2) + 1.5kg(9.8m/s^2)(2m) Ef= 0.75 + 0.075 + 29.4 Ef= 30.225 Joules Does this seem right?