The binding energy (BE) per nucleon for 235U is 7.6 Mev. The 235U undergoes a nuclear fission to produce two fragments both having a BE of 8.5Mev. What is the energy released from a complete fission of 1kg of 235U (joules)?(adsbygoogle = window.adsbygoogle || []).push({});

Here I assumed that it breaks into two 118X element. Therefore

BE(product) per atom is 2*118*8.5=2006

BE(reactant) per atom is 236*7.6=1793.6

Energy released per atom= 212.4 Mev

Number of atoms in 1 kg U=1/.235*6.022*[itex]10^{23}[/itex] = 2.5625*[itex]10^{24}[/itex]

Total energy = 2.5625*[itex]10^{24}[/itex] *212.4

= 5.4428*[itex]10^{26}[/itex] Mev

= 8.7*[itex]10^{13}[/itex] joules

I want know if my answer is correct ?

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# Energy of fission reaction

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