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Energy of fission

  1. Apr 12, 2008 #1
    1. The problem statement, all variables and given/known data

    Find the energy which comes out with fission of the nucleus of deuterium and tritium, so we receive like product the nucleus of helium.

    mass of tritium[tex]m(\stackrel{3}{1}H)=3,016049u[/tex]
    mass of the nucleus of deuterium [tex]m(\stackrel{2}{1}H)=2,013553u[/tex]
    mass of the nucleus of helium [tex]m(\stackrel{4}{2}He)=4,002603u[/tex]


    2. Relevant equations

    [tex]\Delta E=\Delta m c^2[/tex]

    3. The attempt at a solution

    The nuclear reaction

    [tex]\stackrel{2}{1}H + \stackrel{3}{1}H \rightarrow \stackrel{4}{2}He + \stackrel{1}{0}n + energy[/tex]

    How will I find the mass of triton( the nucleus of tritium) ?
     
  2. jcsd
  3. Apr 12, 2008 #2

    Andrew Mason

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    Take the mass of the atom and subtract the mass of the electron. The binding energy of the electron is not enough to make a significant difference in the mass of the atom.

    AM
     
  4. Apr 13, 2008 #3
    (3,016049u+2,013553u)-(4,002603u+1,008665u)=0,018334

    0,018334*931,494 MeV=17,078011 MeV

    And in my text book results it is 17,8 MeV. Is their fault?
     
  5. May 4, 2008 #4

    malawi_glenn

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