Let's say I have a Positronium atom (an atom formed by an electron and a positron), and that this atom makes a transition from an n=3 state to an n=1 state. How do I find the energy of the photon that gets emitted during this transition?(adsbygoogle = window.adsbygoogle || []).push({});

I've tried to use the Lyman series to find the wavelength. This looks like the following

[tex]

\frac{1}{\lambda}=R\left( \frac{1}{1^2}+\frac{1}{n^{3}} \right)

[/tex]

Setting n=3 I get

[tex]

\frac{1}{\lambda}=\frac{8}{9}R

[/tex]

If energy is E=vh, R=1.097e7m^-1, h=4.14e-15eV*s, and c=2.998e8m/s then

[tex]

E=vh=\frac{c}{\lambda}h=\frac{8}{9}Rch=12.10eV

[/tex]

I am looking for the answer E=6 eV, so I am pretty sure that I am wrong. Can anyone tell me how to do this correctly?

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# Homework Help: Energy of photon emitted from Positronium transition

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