as the radius of an electron orbit increases, the total energy of the electron decreases because of the relationship: [tex]E=\frac{-Z^2E_o}{n^2}[/tex] right? does this means that the electron's kinetic energy would also decreas too?(adsbygoogle = window.adsbygoogle || []).push({});

if I was asked to find the energy of the shortest wavelength photon that can be emitted by a hydrogen atom, I would use:

[tex]\frac{1}{\lambda}=R[\frac{1}{n_1^2}-\frac{1}{n_2^2}][/tex]

[tex]\frac{1}{\lambda}=1.0973731x10^7[\frac{1}{1}-\frac{1}{infinity}][/tex]

[tex]\lambda=91.12667nm[/tex]

so E=hc/91.12667nm=13.605698eV

is this correct?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Energy of proton

**Physics Forums | Science Articles, Homework Help, Discussion**