A 0.05 kg bullet traveling at 200 m/s embeds into a 1.0 kg stationary wood block suspended by two light strings. Find the change in vertical height of the block.
Wnc = 0 ?
mgho + .5mvo^2 = mghf + .5mfv^2
Wnc != 0 ?
.5mvf^2 + mghf - .5mvo^2 - mgho
The Attempt at a Solution
I really have no idea where to start. I'm not entirely sure if the work of the non conservative forces is equal to zero or not. I'm not even sure what I would put as the initial and final velocities ( 200 and 0 respectively??).
If it's Wnc = 0, then I did this:
.5 ( 1.05 ) ( 200^2) = (1.05) (9.8) hf
2100 = 10.29 hf
2100/10.29 = 204.1m = hf
But that seems like a rather high number