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I'm having a bit of trouble finding the right equation for this:

The pulley in the figure has radius 0.160 m and a moment of inertia 0.480. The rope does not slip on the pulley rim.

Use energy methods to calculate the speed of the 4.00-kg block just before it strikes the floor.

To do this, would the following formula be correct?

[tex]m_{1}gh = 1/2m_{1}v^2 + 1/2I\omega^2 + m_{2}gh[/tex]

The initial energy would just be potential, right? The 2kg block on the floor would have 0 potential energy, and 0 kinetic energy...

I'm getting an answer of 2.9352, is this correct?

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# Energy Problem

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