Energy production using hydroelectric

[Vpeloquin]

This is my first post so bear with me. I have available 7600 gallons of water per minute with the head pressure of 150 feet. The question is what size penstock should I use for the delivery of the water to the generator? And what size generator and type would one use to obtain its optimal performance? What are the final kilowatts produced?
If that is too much information to ask for than I can settle on what size pipe would deliver 7600 gallons of water in 1 min. from a height of 150 feet. I do understand that putting a generator at the end of this pipe will create a restriction and reduction in volume that I'm not sure how to account for since I don't know what the generator type or resistance might be. Any help would be appreciated.

 

[Vailanor]

Thank you.To answer your question, you first need to determine the flow rate of water, which is calculated by dividing the total volume (7600 gallons) by the time (1 minute). This gives you a flow rate of 7600 gallons per minute (GPM).Next, you need to determine the size of the penstock and the type of generator. The size of the penstock will depend on the pressure of the water and the flow rate, as well as the type of generator you plan to use. Generally, for a water head of 150 feet, the recommended pipe diameter is around 10-14 inches. The type of generator you choose will also affect the size of the penstock and the power output. You can calculate the power output of the generator by multiplying the flow rate and pressure of the water together. For example, if you are using a hydroelectric turbine, which has an efficiency of around 90%, then the power output would be 7600 gallons x 150ft/2.31 (conversion factor) x 0.9 (efficiency) = 533kW.Finally, you should consider the economic cost of the generator and the penstock, including installation costs, and any maintenance or repairs that may be needed in the future.I hope this information helps. Good luck!