Energy Question!! Please Help!! 1. The problem statement, all variables and given/known data A 170g hockey puck sliding at 25 m/s slows to a speed of 10 m/s in a distance of 7.5m. Determine the force of friction causing the puck to slow down. m=170g = 0.170kg V1 = 25 m/s V2= 10 m/s d = 7.5 m/s 2. Relevant equations Kinetic Energy = (1/2)(m)(v^2) Work = Fd 3. The attempt at a solution I'm really confused... Kinetic Energy 1 = (1/2)(0.170kg)(25m/s) = 2.125 J Kinetic Energy 2 = (1/2)(0.170kg)(10m/s) = 0.85 J Kinetic Energy 2 - Kinetic Energy 1 0.85 J - 2.125 J = -1.325 J Work = Fd F = Work/d = -1.325/7.5m = -0.176666... which is wrong! Please help!!