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Energy reduced by air drag

  1. Oct 11, 2005 #1
    A 49kg skier leaves the end of a ski-jump ramp with a velocity of 28 m/s directed 22o above the horizantal. Suppose that as a result of air drag the skier returns to the ground with a speed of 17 m/s, landing 10 meters vertically below the ramp. From the launch to the return to the ground, by how much is the mechanical energy of the skier-Earth system reduced because of air drag?

    first i found the velocity the skier should have without air drag (31.3075 m/s). then i found the difference between 31.3075 and the actual speed 17m/s. then i used that number and plugged it into 1/2 m v^2 = KE to find the energy lost due to air resistance. 5015 J... this isn't right though. what did i do wrong?
     
  2. jcsd
  3. Oct 12, 2005 #2

    vanesch

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    Staff Emeritus
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    You shouldn't calculate the difference in velocity and then the corresponding hypothetical KE, you should take the difference between the 2 KE (with and without drag).

    cheers,
    Patrick.
     
  4. Oct 12, 2005 #3

    russ_watters

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    Staff: Mentor

    Why: because KE is a square function of velocity, and therefore finding the difference in velocity and plugging that into the KE equation will give the wrong answer.
     
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