hi, this is a basic conceptual question. Assume two identical capacitors of capacitance C without any leakage. potential difference across one capacitor V volts and the other capacitor is 0 volts. now the energy stored on the first cap is 1/2*C*V*V and there is no energy stored on other capacitor. Now if i connect these capacitors in parallel the overall cap is 2C and since there is no way for charge to escape the voltage across the parallel combination will be V/2. now the energy stored in the entire network is 1/2*(2C)*(V/2)^2=1/4*C*V*V. I couldn't figure there the pther half of the energy is gone. please help me understand where i am going wrong in understanding the concept here. thank you.