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Decadohedron

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## Homework Statement

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Using n-Pb collision experimental data, find sigma_0 in units of 1/keV^2 and convert to cm^2

(I'm copy-pasta'ing from Mathematica, sorry for mess)

\[Alpha]n = 7*10^-49m^3;

mn = 939565; <--- Neutron mass in keV/c2

\[HBar] = 1*10^-3; <--- Natural units and again keV*s

b = -0.15*10^-3; <---- keV^-1/2

Z = 82; <--- Lead atomic number

v = 4 \[Pi]/137;

\[Sigma] = ((-2.5*10^-4/b ) * mn^(3/2) * v * \[Alpha]n * Z^2/(\[HBar]^3))^2

## Homework Equations

1ev = 8065.54 / cm

## The Attempt at a Solution

So I got:

Sigma = 4.29446*10^-55 / keV^2

From the ev -> cm equation, I went to 1cm^2 = 8065.54^2/(0.001keV)^2

So on my first attempt I got 2.7936*10^-41, which was wrong.

After typing it out and doing it again I came to 6.60148*10^-69 cm^2 ... That seems a bit better but I"m pretty lost, not going to lie.

Thanks in advance