Homework Help: Energy Tranfers

1. Aug 12, 2007

a) A 15g bullet is fired at 840m/s into a ballistic pendulum consisting of 24 kg bag of sand. |\
| \
| \ { }
| { == }
| { }
15 g ----- /\
=== | 24 kg | | 80 cm
840m/s | sand | |
----- \/

If the baf rises to a height of 80 cm, much enregy is converted into thermal energy?

b)Explain one application of the first law of thermodynamics in this example.

c) Expalin the law of conservation of energy as it applies to this example

ok so i tried this and i rlly dont have a clue i know that Energy mechanical = Epotential + Ekinetic

=mv^2/2 + mg(h)

now thats all i know how do i figure out wat is converted into thermal energy? and is thermal energy mechanical energy?

2. Aug 12, 2007

G01

That is the correct description of mechanical energy. Also, thermal energy is not a type of mechanical energy. Consider the following with this problem. You have an inelastic collision here. What do you know about conservation of MECHANICAL energy in an inelastic collision?

3. Aug 12, 2007

a decrese in Ek will result in a increase of Ep? Change in Em = 0? im very lost

4. Aug 12, 2007

PhanthomJay

The term mechanical energy refers to the sum of the kinetic and potential energies only.

If you calculate the mechanical energy of the bullet and bag before the collision, then calculate the mechanical energy of the bullet and bag at their max height, the difference between these 2 values will be the energy lost to heat and other forms.

5. Aug 12, 2007

the potential energy is 0?

6. Aug 12, 2007

ohhh ok that makes perfect sense so find the Em at the beggening and find the Em at its max hieght then subract the 2 , and why didnt i think of that?

7. Aug 12, 2007

oh also wat is the mass in this question? the mass of the bag and bullet combined? or just the bag or just the bullet?

8. Aug 12, 2007

also wat is my speed in the Em as the bag rises? would i use 840 again as i did when the bag was stationary?

9. Aug 12, 2007

ohhh right my speeed would be zero because at the max hieght there is no speed

10. Aug 12, 2007

ok i get around 8500J for my begginign energy and about 20J for my ending energy does that make sense that 8480J would be thermal energy???

11. Aug 12, 2007

G01

The mass you use depends on what part of the problem you are at. When you are calculating the initial mechanical energy, it is all contained in the bullet, so you would use the bullet's mass. While calculating the mechanical energy at the final height of the system, it is the bullet AND the bag that have moved to that height, so the mass used would be their combined mass. Does this answer your question on the mass?

12. Aug 12, 2007

G01

My answer isn't that high. I am getting a lower number for my initial mechanical energy, and a higher number for my final mechanical energy. You should loose a lot of energy to thermal energy, but it's not that much. Check your numbers and units again. Don't worry, I think your on the right track here.

13. Aug 12, 2007

also wat about b and c?

14. Aug 12, 2007

ohh ok so the mass for the initial is just 0.015 kg ok soo there is not hieght so thats adding no potential energy so i got 0.015(840)^2/2 ok so thats 5300J while my Em will be 18.80J so thats thermal energy of like 5288 j?

15. Aug 12, 2007

that sound right?

16. Aug 12, 2007

srry i gotta keep posting these to see if u responded or not...

17. Aug 12, 2007

learningphysics

I get initial Ek = (1/2)(0.015)(840^2) = 5292J
I get Em= mgh= (24.015kg)(9.8)(0.8m)= 188.3J

So thermal = 5292-188.3 = 5103.7J

Last edited: Aug 12, 2007
18. Aug 13, 2007

ohhh right i was doing 80 centimatres was 0.08 metres hahahaha whooops simple math too ok how about b and c?? anyone can help me out?

19. Aug 13, 2007

learningphysics

well for b) remember that thermal energy = internal energy...

can you relate the internal energy of the sandbag to the work done by the sandbag on the bullet use the first law of thermodynamics?

c) well here just explain how the kinetic energy in the bullet transforms to heat and gravitational potential energy...