Energy/Work/Force HW question

  • Thread starter b-pipe
  • Start date
  • #1
14
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Homework Statement


A force acting on an object moving along the x axis is given by Fx = 10x-2.0x2 N where x is in m. How much work is done by this force as the object moves from x = -1 to x= +6

Distance = 7 m

Homework Equations


Work = Force * Distance cosine theta

The Attempt at a Solution


The equation for force is already given so I found force by integrating the equation Fx = 10x-2.0x2 to get Fx = 10-4.0x then I substituted the x for 7 to get -18 Joules. The problem I have is that the answer I got isn't among the options.
 

Answers and Replies

  • #2
218
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You differentiated instead of integrated.
 
  • #3
mukundpa
Homework Helper
524
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and Put the limits for x properly from -1 to +6, (Wx=+6 - Wx=-1)
 
  • #4
14
0
You differentiated instead of integrated.

and Put the limits for x properly from -1 to +6, (Wx=+6 - Wx=-1)

Oh, I see thanks.
 

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