A force acting on an object moving along the x axis is given by Fx = 10x-2.0x2 N where x is in m. How much work is done by this force as the object moves from x = -1 to x= +6
Distance = 7 m
Work = Force * Distance cosine theta
The Attempt at a Solution
The equation for force is already given so I found force by integrating the equation Fx = 10x-2.0x2 to get Fx = 10-4.0x then I substituted the x for 7 to get -18 Joules. The problem I have is that the answer I got isn't among the options.