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Engery of a spring mass system

  1. Mar 23, 2009 #1
    1. The problem statement, all variables and given/known data
    Use your program for the viscously damped spring to solve this problem. Make sure you change the parameters as specified below.

    A mass m=7.5 kg is attached to the end of a spring with a spring constant of k=18.3 N/m. The mass moves through a viscous damping medium with a damping constant b=1.8 kg/s giving a velocity dependent damping force Fdamp= -bv.

    The motion occurs in zero gravity so set the force of gravity to ZERO in your program. Also set the equilibrium position L0=0. The mass is initially motionless and displaced from equilibrium by a distance yinitial=0.2 m.

    What is the energy of the spring-mass system at the initial position of the mass? (the spring-mass system does not include the damping medium)

    What is the energy of the spring-mass system when the mass first passes through the equilibrium position? (you may wish to include a logical test to help you find when this occurs)


    2. Relevant equations
    1/2mv^2
    mgy


    3. The attempt at a solution
    just tried m*g for the first one so far.
     
  2. jcsd
  3. Mar 23, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    Without knowing what your program is, it's a little hard to know what you are struck on.
     
  4. Mar 24, 2009 #3
    from __future__ import division
    from visual.graph import *

    scene.y = 400 # moves animation window down 400 pixels to make room for graph


    # Constants
    pi = 3.14159
    L0 = .08 # equilibrium length of spring (not stretched)
    g = 0 # gravitational acceleration set to zero (not on earth)
    k = 14 # insert the spring constant you found for the coiled spring

    # Objects
    # Ceiling to hang spring from.
    # block to act as mass.
    # Spring is represented by a cylinder.
    scene.center = vector(0,-.1,0) # you may want to adjust this to improve display

    ceiling = box(pos=vector(0,0,0), size=(.3,0.005,0.005)) # make the contact pointthe origin
    block=box(pos=vector(0,-0.1,0), size=(.02,0.02,0.02), color=color.yellow)

    # Using the positions of the block and ceiling set the cylinder to stretch from the ceiling to the block
    spring = cylinder(pos=ceiling.pos, axis=block.pos, radius=.005)

    # Initial values
    block.m = 0.45 # insert the measured mass from coiled spring experiment.
    block.v = vector(0,0,0) # the vector velocity assuming the block is initially stationary
    block.p= block.m * block.v

    block.pos=vector(0,-L0-0.05,0) # initial position of block 0.05m from equilibrium

    # Setting the timestep and zeroing the cumulative time
    deltat = .0001 # you should decrease this later to test if it is small enough
    t = 0
    W = 0
    displacement=0
    Kgraph = gcurve(color=color.cyan)
    Ugraph = gcurve(color=color.yellow)
    KplusUgraph = gcurve(color=color.red)
    Wgraph = gcurve(color=color.green)
    # Loop for repetitive calculations
    scene.autoscale=0
    while t < 4:

    Fnet= -(((block.pos-vector(0,-L0,0))*k))-((block.p/block.m)*.2) #INSERT the force of the spring on the block
    displacement=(mag(block.p)/block.m)*deltat
    block.p= block.p+Fnet*deltat # updates the momentum
    block.pos= block.pos+block.p/block.m*deltat # updates the position
    spring.axis = block.pos #updates the spring axis so it stays on the block
    t=t+deltat
    pmag = mag(block.p) # or whatever you've called the block's momentum

    K = (pmag**2)*.5/block.m #COMPLETE this for the kinetic energy of the
    block
    U = ((mag(block.pos)-L0)**2)*.5*k #COMPLETE this for the potential energy of the block-spring system (note no gravity)
    W = W - displacement*(mag(block.p)/block.m)*.2
    Kgraph.plot(pos=(t,K))
    Ugraph.plot(pos=(t,U))
    KplusUgraph.plot(pos=(t,K+U))
    Wgraph.plot(pos=(t,W))
     
  5. Mar 24, 2009 #4
    this is the program need to solve this problem, but i don't know what # need to be changed to solve this problem

    if someone could help me that would be great
     
  6. Mar 24, 2009 #5
    hi the energy of the spring-mass system at the initial position of the mass will be
    the potential energy only which is
    1/2 * k * x^2

    and then plug the number in
    .5 * 18.3 * (.2)^2 = .366
     
  7. Mar 13, 2010 #6
    how would you solve their 2nd question?!

    "What is the energy of the spring-mass system when the mass first passes through the equilibrium position? (you may wish to include a logical test to help you find when this occurs)"
     
  8. Mar 19, 2010 #7
    Well I'd assume that Since Ef = Ei + Wsurr,
    And they gave us how to solve the Fdamp = -bv.
    So would it be something like Ef = Ei + (Fdamp * x)? Just a guess, I'm in the same mess.
     
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