Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Classical Physics
Quantum Physics
Quantum Interpretations
Special and General Relativity
Atomic and Condensed Matter
Beyond the Standard Model
Cosmology
Astronomy and Astrophysics
Other Physics Topics
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Classical Physics
Quantum Physics
Quantum Interpretations
Special and General Relativity
Atomic and Condensed Matter
Beyond the Standard Model
Cosmology
Astronomy and Astrophysics
Other Physics Topics
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Physics
Quantum Physics
Quantum Interpretations and Foundations
Ensembles in quantum field theory
Reply to thread
Message
[QUOTE="A. Neumaier, post: 6823972, member: 293806"] In general, yes. But in the current experiment you already agreed that the state was the vacuum state. The detector is a glass bottle, on which I find after sufficient time a faint spot of silver. In this simple experiment, correlations cannot be measured, hence we only need 1-point functions. Since silver is uncharged. I guess you regard the mass as a charge. Thus do you agree that the correct operator to look at is the mass 4-current, and especially its zero component, the mass density? Please mimic it for me, so that we can discuss its consequences. Since silver is heavy, I want to use a nonrelativistic QFT, with an antisymmetrized Fock space to account for the spin 1/2 of silver. But we already agreed that the initial state of the beam is the vacuum state, before the oven is switched on. Since we are in the Heisenberg picture, this will be its state throughout the whole day modeled. Thus you somehow need to get the thermal input into the boundary conditions for the observable of interest. And the lab is in a local equilibrium state described by the properties of the stuff inside. We are only looking at the region where the beam is, where the state is even simpler - just the vacuum state. [/QUOTE]
Insert quotes…
Post reply
Forums
Physics
Quantum Physics
Quantum Interpretations and Foundations
Ensembles in quantum field theory
Back
Top