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Honorable_Death
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i was just wondering, if you have two entangled particles and one of them is destroyed, does the entanglement also get destroyed, and would anything else happen?
In normal circumstances, there's no way to "destroy" a particle. You can have it "interact" with something else (say, an anti-particle) but that will always result in yet other particles coming out, depending on the state of the incoming (to be destroyed) particle, and as such, the "entanglement" lives on. There is big discussion of whether this is also true for a black hole.Honorable_Death said:i was just wondering, if you have two entangled particles and one of them is destroyed, does the entanglement also get destroyed, and would anything else happen?
Sorry I really get confused. According to information theory, entropy is loss of information. If loss of information is impossible, how comes the second law of thermodynamics?tabasco said:Whenever you "destroy" a particle, you alway end up with a different particle or photons or whatever. All information that was carried by the particle will be coded in some form in the new particles you get. It is impossible to comletely destroy even just one bit of information without that information dissipating somewhere.
Suppose one of two entangled photons is absorbed by an electron, which subsequently emits a photon of the same wavelength. Can I expect the new photon to be entangled with the other un-destroyed photon? I thought aborption and re-emission cause quantum decoherence and loss of entanglement.The remaining particle will still be entangled with wathever is now carrying the information of the destroyed particle.
vanesch said:In normal circumstances, there's no way to "destroy" a particle. You can have it "interact" with something else (say, an anti-particle) but that will always result in yet other particles coming out, depending on the state of the incoming (to be destroyed) particle, and as such, the "entanglement" lives on. There is big discussion of whether this is also true for a black hole.
Is, or isn't, a particle destroyed when it falls into a black hole ?
Of course that's a difficult question to answer. Classically, in GR, one would be tempted to say that it is... except for one detail. If the black hole is embedded in a minkowki background (meaning, far away from the black hole, spacetime is "flat"), then, for an observer far away, it takes eternity for him to see the particle fall into the black hole. If the black hole now evaporates in a finite amount of time (for the remote observer) then maybe the information got out before even disappearing.
As long as one doesn't have a decent unification of GR and quantum theory, the question will remain open, I suppose.
Honorable_Death said:But when a particle interacts with a anti-particle they get Annihilated and turn into energy,
wywong said:Sorry I really get confused. According to information theory, entropy is loss of information. If loss of information is impossible, how comes the second law of thermodynamics?
Suppose one of two entangled photons is absorbed by an electron, which subsequently emits a photon of the same wavelength. Can I expect the new photon to be entangled with the other un-destroyed photon? I thought aborption and re-emission cause quantum decoherence and loss of entanglement.
Wai Wong (QM newbie)
Since you agree with me that past, presence and future equally exist from the spacetime point of view (we had a discussion about that a long time ago), you might like this:vanesch said:In normal circumstances, there's no way to "destroy" a particle. You can have it "interact" with something else (say, an anti-particle) but that will always result in yet other particles coming out, depending on the state of the incoming (to be destroyed) particle, and as such, the "entanglement" lives on. There is big discussion of whether this is also true for a black hole.
Is, or isn't, a particle destroyed when it falls into a black hole ?
Of course that's a difficult question to answer. Classically, in GR, one would be tempted to say that it is... except for one detail. If the black hole is embedded in a minkowki background (meaning, far away from the black hole, spacetime is "flat"), then, for an observer far away, it takes eternity for him to see the particle fall into the black hole. If the black hole now evaporates in a finite amount of time (for the remote observer) then maybe the information got out before even disappearing.
As long as one doesn't have a decent unification of GR and quantum theory, the question will remain open, I suppose.
tabasco said:All information that was carried by the particle will be coded in some form in the new particles you get. It is impossible to comletely destroy even just one bit of information without that information dissipating somewhere.
An entangled particle refers to a pair or group of particles that have interacted in such a way that their quantum states are linked or "entangled". This means that the state of one particle cannot be described independently of the other, no matter how far apart they are.
Entangled particles can be created through a variety of methods, such as using a laser to split a photon into two entangled photons, or by cooling a material to extremely low temperatures to create entangled electron pairs.
No, entangled particles cannot be destroyed. Even if one of the particles is destroyed or changes its state, the other particle's state will still be affected due to their entanglement.
Entangled particles have potential applications in quantum computing, cryptography, and communication. They can also be used for precise measurements and sensors.
The destruction of an entangled particle can result in a loss of information and disruption of the entanglement between particles. This can affect the accuracy and reliability of any technology or experiments that rely on entangled particles.