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Enthalpy of formation- NaCl & KCl

  1. May 1, 2012 #1
    1. The problem statement, all variables and given/known data
    In my book it is given that ΔHffor NaCl is less negative than that for KCl.
    I'm not able to understand that..........I think that electrostatic attractions between Na+ and Cl- will be stronger than K+ & Cl- as Na has smaller size than K......in its formation more energy should be released and ΔHffor NaCl should be more negative.

    I also noticed that in case of F my reasoning seems correct.


    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. May 1, 2012 #2
    please reply someone.....thanks
     
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