1. The problem statement, all variables and given/known data Using the enthalpies of formation given below, calculate ΔH°rxn in kJ, for the following reaction. 3NO2(g)+1H2O(l) -> 2HNO3(g)+1NO(g) NO2 (g): 33.10 kJ/mol H2O (l): -285.83 kJ/mol HNO3 (l): -174.10 kJ/mol NO (g): 90.29 kJ/mol 2. Relevant equations dHrxn = dHproducts - dHreactants 3. The attempt at a solution Is this possible to do since the equation says HNO3 is a gas, but they give the enthalpy of formation for HNO3 as a liquid.