(adsbygoogle = window.adsbygoogle || []).push({}); 2. Relevant equations

d ln(Psat) / d (1/T) = -ΔHvap/R (Clausius-Clapeyron)

3. The attempt at a solution

When solving for the enthalpy of vaporization using the Clausius-Clapeyron equation, is the resulting value an average over the temperature range? I assume this is the case, because enthalpy of vaporization is dependent on temperature.

I found the enthalpy of vaporization for carbon dioxide from 220K to 300K to be 16.59 kJ/mol (using the Clausius-Clapeyron equation) and tabulated saturation pressures.

I'm comparing this to the value I get from Hv-Hl=ΔHvap. When I take an average (arithmetic mean) of these values over the same temperature range, I get a value of 11.4 kJ/mol.

Why is there such a difference between using these two methods?

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# Homework Help: Enthalpy of vaporization from Clausius–Clapeyron

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