(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

An ice cube (mass 30 g) at 0 degrees celsuis is left sitting on the kitchen table, where it graduallyy melts. The temperature in the kitchen is 25 degrees celsuis. Calculate the entropy of the water (from melted ice ) as its temperature rises from 0 degrees celsuis to 25 degrees celsuis.

2. Relevant equations

c(ice)=2.0 J/g*C

c(water)=4.18 J/g*C

delta(S)= Q/T; Q=C*delta(T)=c*m*delta(T)/T

3. The attempt at a solution

delta(S)= Q/T=c*m*delta(T)/T= ((4.18)*(30 g)*(25 Kelvins))/298 Kelvins= 10.52 J/K

**Physics Forums - The Fusion of Science and Community**

# Entropy and heat

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Entropy and heat

Loading...

**Physics Forums - The Fusion of Science and Community**