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Physics
Classical Physics
Thermodynamics
Entropy change of environment during an irreversible process
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[QUOTE="crick, post: 5503534, member: 568971"] What is the [URL='https://www.physicsforums.com/insights/grandpa-chets-entropy-recipe/']change in entropy[/URL] of thermodynamic environment [U]if it changes its temperature during the process and the process is not reversible[/U]? I'm slightly confused because, on the one side, in that case ##\Delta S_{gas} \neq -\Delta S_{surroundings}##, since ##\Delta S_{universe} >0## but on the other hand ##\Delta S## does not depend on the specific process, so it should be the same as in a reversible one (and, in a reversible process, ##\Delta S_{gas} =-\Delta S_{sourroundings}##). For istance, for an ideal gas we can calculate ##\Delta S## using a reversible transformation, even if the real transformation it is not. What am I missing here? So how can one calculate the entropy change of the environment in such cases? [/QUOTE]
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Physics
Classical Physics
Thermodynamics
Entropy change of environment during an irreversible process
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