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How do i calculate the entropy change for an isobaric process, if i know
T1, T2, n and Cv ?
Thanks,
T1, T2, n and Cv ?
Thanks,
Correct, you can now use this in conjunction with the information which astrorob provided to calculate the entropy change.entropy change = dS = int( dQ/T )
where you integrate from state 1, to state 2.
Indeed, the formula does only hold for a reversible process, but it may be useful to note that since entropy is a state function it is independent of the path taken and depends only on the initial and final states. Therefore, for any process, even an irreversible one, we can chose a reversible path between the initial and final states that allows us to calculate the change in entropy.The forumula only holds for reversible processes and i don't know if thats the case in my question.
The only thing that concerns me is the C_{v}. Since the process is isobaric, you need C_{p}. Apart from that your expression is correct.so i shoud insert the value for dQ = nCvdT and by that getting
dS = int( (n Cv dT)/T) = n Cv ( (1/T) dT ) = nCv ln(T2/T1) ?
Is that correct, even though the process is not reversible?