1. The problem statement, all variables and given/known data A 1.30×10-2 Kg cube of ice at an initial temperature of -12.0 C is placed in 0.470 Kg of water at 50.0 C in an insulated container of negligible mass. mi=1.3x10-2 Kg mw=0.470 Kg Ti=-12 C Tw=50 C ci=2100 cw=4190 Lf=3.34*10^5 2. Relevant equations Qi=Qw S=Q/T 3. The attempt at a solution okay so first I tried to find Tf Qi=Qw mi(Lf+ci(Tf-Ti))=mwcw(Tw-Tf) 1.3x10-2(3.34*105+2100(Tf+12))=0.47*4190(50-Tf) 27.3Tf+327.6+4342=-1969.3Tf+98465 Tf=46.98 for entropy I tried to add up all the stages where ice->0 C + ice->water + ice water->Tf + hot water->Tf S=[miciln(T2/Ti)]+[miLf/T]+[micw ln(Tf/T)]+mwcw ln(Tf/Tw) S=[1.3x10-2*2100ln(273.15/261.15)]+[(1.3x10-2*3.34x105/273.15)]+[1.3x10-2*4190 ln(46.98+273.15/273.15)]+[0.470*4190 ln(46.98+273.15/50+273.15)] =1.2264+15.896+8.644-18.490=7.28 I still get the wrong answer when using this method so if someone could point me in the right direction that would be much appreciated.