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Entropy of a rubber-band (force determined by entropy or energy)?
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[QUOTE="Chestermiller, post: 4394242, member: 345636"] According to Eqn. 11, the slope is [itex](\frac{\partial f}{\partial T})_l=-(\frac{\partial S}{\partial l})_T[/itex] and the intercept is [itex](\frac{\partial U}{\partial l})_T[/itex]. The question is: which makes a bigger contribution to the force f, [itex](\frac{\partial U}{\partial l})_T[/itex] or [itex]T(\frac{\partial f}{\partial T})_l=-T(\frac{\partial S}{\partial l})_T[/itex]? I think what you will find is that the entropy term makes a much bigger contribution to the force than the energy term. This is because the configurational entropy change associated with the extension of the polymer molecules when the rubber is deformed relates to the molecules acting like microscopic springs. [/QUOTE]
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Entropy of a rubber-band (force determined by entropy or energy)?
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