- #1
evry190
- 13
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Okay so here's the limit lim(as x --> -1) 2x^2=2
I have |2x^2-2| < 1
2|x + 1||x - 1| < 1
|x + 1||x - 1| < 1/2
and 0 < |x + 1 | < delta
-1 - delta < x < -1 + delta
|x - 1| < -2 + delta
|x + 1| < 1/2(-2 + delta)
so is delta = 1/2(-2 + delta) correct? if so, how do i know which answer (since there will be 2) is right?
I have |2x^2-2| < 1
2|x + 1||x - 1| < 1
|x + 1||x - 1| < 1/2
and 0 < |x + 1 | < delta
-1 - delta < x < -1 + delta
|x - 1| < -2 + delta
|x + 1| < 1/2(-2 + delta)
so is delta = 1/2(-2 + delta) correct? if so, how do i know which answer (since there will be 2) is right?