I'm supposed to prove that lim x -> -2, x^2+3x+7 = 5(adsbygoogle = window.adsbygoogle || []).push({});

Here's what I have:

|x^2 +3x+7 – 5| < ε

|x+2| < δ

|x^2+3x+2| -> |(x+2)(x+1)| < ε whenever |x+2| < δ

|x+1||x+2| < δ |x+1|

|x+1||x+2| < δ|x+1| < ε

ε / |x+1| > δ , as x -> -2, |x+1| -> 3,

therefore: ε / -1 > δ

But I'm not sure if I did it correctly, since its our first time using quadratic. Help, please?

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# Homework Help: Epsilon Delta proof help

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