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## Homework Statement

lim 3 as x->6

lim -1 as x->2

## Homework Equations

In the first weeks of a calculus class and doing these epsilon delta proofs.

As i am looking at two of the problems i have been assigned:

Lim 3 as x->6

Lim -1 as x->2

## The Attempt at a Solution

considering both are horzontal lines, if i give some ε then there is no intersection with the function and thus no δ. ε must be > 0 so not sure how our proof statement will work:

Given ε>0, choose δ=ε. If 0<0<δ, then |0|<δ, then |3-3| = |0| < δ=ε thus |3-3|<ε whenever 0<|0|<δ. Therefore, by the definition of a limit, lim 3 = 3 as x->6