Equal area axis

  • Thread starter fonseh
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  • #1
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Homework Statement


For this shape , it's clear that the centroid and the horizontal line of equal axis lies on the same horizontal line , am i right ????

Homework Equations




The Attempt at a Solution


I'm not sure . correct me if i am wrong . [/B]
 

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Answers and Replies

  • #2
35,135
6,884

Homework Statement


For this shape , it's clear that the centroid and the horizontal line of equal axis lies on the same horizontal line , am i right ????

Homework Equations




The Attempt at a Solution


I'm not sure . correct me if i am wrong . [/B]
Do you mean "line of equal area"?
Anyway, yes, symmetry should convince you that you're right if there's no other information given.
 
  • #3
529
2
Do you mean "line of equal area"?
Anyway, yes, symmetry should convince you that you're right if there's no other information given.
Are you familiar with plastic analysis ? Zp here is the plastic modulus .

I use another method to do , but i get different answer , why ?

Here's my working : , Zp = Sum of area x ( difference between centroid of particluar area and the equal area axis )

Zp = [ (130)(20)(150-10) + (150)(20)(150/2) ] x 2 = 1178000 , but the ans provided is only 929040
 
  • #4
35,135
6,884
Are you familiar with plastic analysis ?
No, I'm not, but I am familiar with the concept of centroids.
My answer is based on the fact that the shape in the drawing is symmetric about its horizontal midline.
fonseh said:
Zp here is the plastic modulus .

I use another method to do , but i get different answer , why ?

Here's my working : , Zp = Sum of area x ( difference between centroid of particluar area and the equal area axis )

Zp = [ (130)(20)(150-10) + (150)(20)(150/2) ] x 2 = 1178000 , but the ans provided is only 929040

If you had a rectangular piece of some uniform, rigid material 150 mm by 300 mm, its centroid would be at the center of the piece, at a point 75 mm to the right of the left edge, and 150 mm above the lower edge. If you cut out a rectangle 130 mm by 260 mm to form a "C" shape as in your drawing, the centroid of the piece you remove would be at its center, and the centroid of the remaining C-shaped piece would be along the horizontal midline, but a bit right of where it was for the original uncut piece of material.
 
  • #5
PhanthomJay
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Your number looks correct for the plastic section modulus perhaps the book is looking for the elastic section modulus you'll have to run the numbers
 

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