1. The problem statement, all variables and given/known data Q) To pull a car from a ditch, the driver ties one end of a rope to the car and the other end to a tree 12.5 m away and then pulls sideways at the midpoint of the rope with a 475 N force. How much force is exerted on the car when the driver has pulled the rope 75.0 cm to one side ? The book's answer 1990N. 2. Relevant equations 3. The attempt at a solution My solution assuming this is a torque issue. Assuming> the ends are 12.5 meters apart.one end tied to the car, the other tied to the tree. > driver is pulls the rope 75 cm from the middle 6.25meters. So the radius = 12.5metres/2 = 6.25meters Find Ɵ 0.12 = sin Ɵ. Ɵ = 6.89 The torque is rFsinƟ = 6.25m ( 475N) sin6.89 = 356Nm. My solution assuming this is an equilibrium issue: Assuming> the ropes ends are 12.5 meters apart. > The ropes directions are one end is to the east and the other is to the west > assuming the driver is pulling the car 75 cm west of north. So the radius = 12.5metres/2 = 6.25meters Find .75metes / 6.25 meters = 0.12 = cos Ɵ. Ɵ = 83.1 westward - The driver force on the car will be 475Ncos83.1= 57N Northward - The driver force on the car will be 475Nsin83.1= 471N thanks for your time!