(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Q) To pull a car from a ditch, the driver ties one end of a rope to the car and the other end to a tree 12.5 m away and then pulls sideways at the midpoint of the rope with a 475 N force. How much force is exerted on the car when the driver has pulled the rope 75.0 cm to one side ?

The book's answer 1990N.

2. Relevant equations

3. The attempt at a solution

My solution assuming this is a torque issue.

Assuming> the ends are 12.5 meters apart.one end tied to the car, the other tied to the tree.

> driver is pulls the rope 75 cm from the middle 6.25meters.

So the radius = 12.5metres/2 = 6.25meters

Find Ɵ

0.12 = sin Ɵ.

Ɵ = 6.89

The torque is rFsinƟ = 6.25m ( 475N) sin6.89 = 356Nm.

My solution assuming this is an equilibrium issue:

Assuming> the ropes ends are 12.5 meters apart.

> The ropes directions are one end is to the east and the other is to the west

> assuming the driver is pulling the car 75 cm west of north.

So the radius = 12.5metres/2 = 6.25meters

Find

.75metes / 6.25 meters = 0.12 = cos Ɵ.

Ɵ = 83.1

westward - The driver force on the car will be 475Ncos83.1= 57N

Northward - The driver force on the car will be 475Nsin83.1= 471N

thanks for your time!

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# Homework Help: Equalibrium problem ( i think)

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