Equality Reaction: Questions & Answers - Fred

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In summary, the equilibrium shifts one side if the concentrations of the reactants can be changed. This could be done by reacting with more O2 to yield NO2.
  • #1
Mathman23
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Hi

I got two questions:

1] A equality reaction:
[itex]\mathrm{2N + O_{2} \rightleftharpoons 2NO}[/itex]

a) How does one remove NO from the reaction?


2] An equality mixture [itex] \mathrm{H_2 + Br_2 \rightleftharpoons 2 HBr}[/itex]

contains 0,340 mol [itex]H_2[/itex] , 0,220 mol [itex]\mathrm{Br_2}[/itex].

in a canister which has a volume V = 1,0 L.

The mixture is heated to reaches a tempeture of 700K.

Then the reaction has set itself 0,0196 mol is left of [itex]Br_{2}[/itex]

a) The concentration of [itex]\mathrm{C_{H_2} = \frac{0,34 mol}{1,0 L} = 0,34 mol/L}[/itex]

The concentration of [itex]\mathrm{C_{Br_2} = \frac{0,22 mol}{1,0 L} = 0,22 mol/L}[/itex]

b) The equality fraction for the reaction is: [itex]\mathrm{K_c} = \frac{\mathrm{[HBr]^2}}{\mathrm{[H_2] \cdot [Br_2]}}[/itex]

c) How do I obtain [HBr] ?

Sincerely

/Fred
 
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  • #2
Hello,

An equilibrium may shift either side if the concentration of the contributors can be changed. You may try this by further reacting with O2 to yield NO2.

[tex]NO+\frac {1}{2} O_2 \leftrightharpoons NO_2[/tex]

About your second question, I think you are finding the initial concentrations. This may be incorrect as you seem to omit something. At 700°C, the available hydrogen is completely reacted with oxygen to give water. I don't know any change would be present in HBr and Br2.

You may find that 0,120 mols of hydrogen is excess in the medium, so it can be converted to water via the reaction [itex]H_2+ \frac {1}{2}O_2 \rightarrow H_2O[/itex]. After the equilibrium is reached, you state that 0,0196 moles of bromine is present. You can do the rest from here, if you're stuck somewhere, don't hesitate to ask.
 
  • #3
Hi there,

[itex]\mathrm{K_c} = \frac{\mathrm{[HBr]^2}}{\mathrm{[H_2] \cdot [Br_2]}}[/itex]

Where i = initial and f = final

[H2init--][Br2init]--[2HBr2init]
[0.340--][0.220 ]--[2---x---]
[H2Fin--]Br2Fin ]--[2HBr2fin]
[0.1396 ][0.0196]--[2---x--]

/_\ = 0.2004

So 2HBr = 2 x /_\ = 2 x 0.2004.

So Concentration = 2/_\ / Volume = 2 x 0.2004 / 1 = well you can do that :-)

And then you can easily calculate the Kc.

Wolfson.
 
Last edited:

1. What is an equality reaction?

An equality reaction is a chemical reaction where the number of atoms of each element on the reactant side is equal to the number of atoms of the same elements on the product side. This means that the mass of the reactants and products are balanced, resulting in no net change in the overall amount of matter.

2. How is an equality reaction different from other chemical reactions?

An equality reaction is unique because it ensures that all atoms are accounted for and none are lost or gained during the reaction. This is different from other reactions where atoms may be lost or gained, resulting in an overall change in mass.

3. Can an equality reaction occur in both physical and chemical changes?

Yes, an equality reaction can occur in both physical and chemical changes. In physical changes, the atoms and molecules remain the same, but the arrangement may change. In chemical changes, new substances are formed, but the total number of atoms remains the same.

4. How do scientists use equality reactions in their research?

Scientists use equality reactions to understand the fundamental principles of chemistry, such as conservation of mass. They also use these reactions to create new substances and study the properties and behavior of different elements and compounds.

5. What are some real-world applications of equality reactions?

Equality reactions have many real-world applications, including in industrial processes such as the production of fertilizers, plastics, and fuels. They are also used in environmental analysis to determine the composition of various substances. In addition, equality reactions are essential in the manufacturing of pharmaceuticals and agricultural chemicals.

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