- #1
- 82
- 0
2x^2 − 12x + p = q(x − r)^2 + 10 for all values of x find p q and r
i've got
2(x-3)^2 + p = Q(x-r)^2 + 10
so q = 2 r = 3 and p = 10?
now the answers say that Q = 2 r = 3 and p = 28?
can someone explain how to properly go about doing this equation.
i've got
2(x-3)^2 + p = Q(x-r)^2 + 10
so q = 2 r = 3 and p = 10?
now the answers say that Q = 2 r = 3 and p = 28?
can someone explain how to properly go about doing this equation.