- #1

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i've got

2(x-3)^2 + p = Q(x-r)^2 + 10

so q = 2 r = 3 and p = 10?

now the answers say that Q = 2 r = 3 and p = 28?

can someone explain how to properly go about doing this equation.

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- Thread starter DeanBH
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- #1

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i've got

2(x-3)^2 + p = Q(x-r)^2 + 10

so q = 2 r = 3 and p = 10?

now the answers say that Q = 2 r = 3 and p = 28?

can someone explain how to properly go about doing this equation.

- #2

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2x^2 − 12x is not the same as 2(x-3)^2

- #3

HallsofIvy

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