- #1

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Equation for the parabola with the given vertex that passes through the given point.

I am stumped! Please help

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- Thread starter TonyC
- Start date

- #1

- 86

- 0

Equation for the parabola with the given vertex that passes through the given point.

I am stumped! Please help

- #2

- 138

- 0

you have a quadratic of the form ax^2+bx+c

so you have two points

so plug in y and x in for those two points:

5=25a-5b+c

and

17=9a-3b+c

but they also tell you that (-5, 5) is the vertex

which means that there, the solution only has one root; meaning that the x coordinate is equal to -b/2a

so then you have

-5=-b/2a

i think you should be able to solve for this now. perhapsably.

- #3

- 86

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Using what is provided, I have come up with:

y=3(x+5)^2+5

y=3(x+5)^2+5

- #4

Galileo

Science Advisor

Homework Helper

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TonyC said:Using what is provided, I have come up with:

y=3(x+5)^2+5

Great. This is always the most insightful way to write the equation of a parabola.

As a check, you can easily see the vertex is at (-5,5). Putting x=-3 gives y=3(2^2)+5=17.

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