 #1
Shubh Goel
 10
 1
 TL;DR Summary

Assuming travelling at speed of light is possible.
If i leave earth at the speed of light, two things will happen:
A. On observing earth, i will see that time has
freezed on it and if i go faster then I will
observe time going backwards.
B. For those on earth, as the observers see
me, they will see me traveling at speed of light
but there will be a time difference in which
they see me and one in which i am. I will have
already done what they see.
For case B
Conditions:
1. The observer was observing since the time they were in contact.
2. There are only 2 directions for motion: back and forward.
3. Relative velocity is not equal to zero.
4. Bodies are moving away from each other
Time difference = t
Relative velocity = v
Distance between position of source of the beam of light the observer is seeing and the observer= x
C= speed of light
The equation comes out to be T=vx/c^2
Conditions:
1. The observer was observing since the time they were in contact.
2. There are only 2 directions for motion: back and forward.
3. Relative velocity is not equal to zero.
4. Bodies are moving away from each other
Time difference = t
Relative velocity = v
Distance between position of source of the beam of light the observer is seeing and the observer= x
C= speed of light
The equation comes out to be T=vx/c^2