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Equation:I=Ioe^(eV/(kt)),so the graph to find e and Io is lnI against V?Nid c pic...
SOLVED-I managed 2 call my teacher and he solved it
-Zooms[tex]Equation\ is\ I=I_{o}e^\frac{eV}{kT}[/tex]
Edit ** Yo .This is my question paper and I've written some working on it.I've 2 questions-part a)The graph needed to find e and Io is ln I against V is it? & for last part,e) to find the uncertainty of e I think I need the uncertainty of the y value,but they all are different at different pts,so I average them up in order to get e,correct way?!
Uncertainty calculation:
For getting the uncertainty,b in a,a[tex]\pm[/tex]b
-If multiplication involved in calculating a then add fractional uncertainties then multiply by a to get b.
-If addition or minus involved in calculating a just add uncertainties only to get b
For natural logarithm: lne=1
Well,I start by doing ln on both sides of the equation given ,ln I=lnIo + (ev)/(kt),then comparing it to y=mx+c the y is lnI,the x is V.Thus I think I need lnI against V to get the e and Io.I'm just checking the answer with u and at the same time doing my studies for my A lv(Which 2day is my exam for this type of questions).Hope the correct answer is answered here.So correct?
Homework Statement
SOLVED-I managed 2 call my teacher and he solved it
Edit ** Yo .This is my question paper and I've written some working on it.I've 2 questions-part a)The graph needed to find e and Io is ln I against V is it? & for last part,e) to find the uncertainty of e I think I need the uncertainty of the y value,but they all are different at different pts,so I average them up in order to get e,correct way?!
Homework Equations
Uncertainty calculation:
For getting the uncertainty,b in a,a[tex]\pm[/tex]b
-If multiplication involved in calculating a then add fractional uncertainties then multiply by a to get b.
-If addition or minus involved in calculating a just add uncertainties only to get b
For natural logarithm: lne=1
The Attempt at a Solution
Well,I start by doing ln on both sides of the equation given ,ln I=lnIo + (ev)/(kt),then comparing it to y=mx+c the y is lnI,the x is V.Thus I think I need lnI against V to get the e and Io.I'm just checking the answer with u and at the same time doing my studies for my A lv(Which 2day is my exam for this type of questions).Hope the correct answer is answered here.So correct?
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