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Equation normal to plane

  1. Jun 9, 2012 #1
    I'm having trouble finding the equation normal to the plane for part (ii).

    The vector equation I got for part (i) is r=(1/2,1,2/3) + t(3/2,2,-2/3). How do you deduce the normal vector from this? The answer is the vector (9,12,-4). I've tried anything but don't know where they got this result.

    Thanks
     

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  2. jcsd
  3. Jun 9, 2012 #2
    They used your (3/2,2,-2/3) and multiplied by 6 to clear the denominator.
     
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