- #1
DeanBH
- 82
- 0
x^2 + y^2 + 2x -12y + 12 = 0
(x-a)^2 + (y-b)^2 = r^2 in that form.
why doesn't this work.
(x+1) + (y-6)
this gives you your x^2 your 2x and a +1 Gives you y^2 and -12y and a +36
so (x+1) + (y-6) + 49 = 0?
that would make r^2 negative which is impossible, what am i screwing up here?
(x-a)^2 + (y-b)^2 = r^2 in that form.
why doesn't this work.
(x+1) + (y-6)
this gives you your x^2 your 2x and a +1 Gives you y^2 and -12y and a +36
so (x+1) + (y-6) + 49 = 0?
that would make r^2 negative which is impossible, what am i screwing up here?
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