Equation of a sine bike wheel

  • Thread starter emma3001
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  • #1
emma3001
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A bike has wheels with diameter 0.6m. The bike moves along the road at 6m/s. Determine an equation for the height of the the speck on the tire above the road as a function of time in t seconds.

I think that the amplitude is 0.3 and my period is 0.6pi (circumference). Would there be any phase shifts left or right, up or down. How would the period be written in the function?

y=0.3sin10pi/3
 

Answers and Replies

  • #2
konthelion
238
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I believe this problem is missing the information as to where the speck starts.

I'll assume that the speck starts at the lowest point of the wheel. There's an equation [tex]v=r\omega[/tex], where v is the velocity, r= radius, and [tex]\omega[/tex]=angular velocity. Therefore, [tex]\omega=\frac{v}{r}[/tex] and also [tex]\omega=\frac{d\theta}{dt}[/tex]

Find [tex]\omega[/tex]
Let's define the height function [tex]h(t) = r(1-cos(\theta))[/tex]. *For this height equation I use the line h(t)=0 as the ground, so you can change the equation if you use h(t)=0 as the center of the wheel. From here, find [tex]\theta [/tex] in terms of t and [tex]\omega[/tex]
 
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