Equation of a tangent

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How do i find the equation of the tangent to the graph given by the equation at the point
P(5pie/6),1) y=2sinx
The answer in the back of the textbook says.
sqroot3X + y - 1 - 5sqroot3pie/6 = 0
 

Answers and Replies

  • #2
what do you need to define a line? gradient and intercept...
 
  • #3
Gradient can be given by the derivative, so find the derivative. And the y-intercept is quite straight forward.
 

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