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How do i find the equation of the tangent to the graph given by the equation at the point
P(5pie/6),1) y=2sinx
The answer in the back of the text book says.
sqroot3X + y - 1 - 5sqroot3pie/6 = 0
P(5pie/6),1) y=2sinx
The answer in the back of the text book says.
sqroot3X + y - 1 - 5sqroot3pie/6 = 0