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Equation of a tangent

  1. Mar 30, 2007 #1
    How do i find the equation of the tangent to the graph given by the equation at the point
    P(5pie/6),1) y=2sinx
    The answer in the back of the text book says.
    sqroot3X + y - 1 - 5sqroot3pie/6 = 0
  2. jcsd
  3. Mar 30, 2007 #2


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    what do you need to define a line? gradient and intercept...
  4. Mar 30, 2007 #3

    Gib Z

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    Gradient can be given by the derivative, so find the derivative. And the y-intercept is quite straight forward.
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